13y^2-5xy-8x^2=0

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Solution for 13y^2-5xy-8x^2=0 equation:


Simplifying
13y2 + -5xy + -8x2 = 0

Reorder the terms:
-5xy + -8x2 + 13y2 = 0

Solving
-5xy + -8x2 + 13y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-8x + -13y)(x + -1y) = 0

Subproblem 1

Set the factor '(-8x + -13y)' equal to zero and attempt to solve: Simplifying -8x + -13y = 0 Solving -8x + -13y = 0 Move all terms containing x to the left, all other terms to the right. Add '13y' to each side of the equation. -8x + -13y + 13y = 0 + 13y Combine like terms: -13y + 13y = 0 -8x + 0 = 0 + 13y -8x = 0 + 13y Remove the zero: -8x = 13y Divide each side by '-8'. x = -1.625y Simplifying x = -1.625y

Subproblem 2

Set the factor '(x + -1y)' equal to zero and attempt to solve: Simplifying x + -1y = 0 Solving x + -1y = 0 Move all terms containing x to the left, all other terms to the right. Add 'y' to each side of the equation. x + -1y + y = 0 + y Combine like terms: -1y + y = 0 x + 0 = 0 + y x = 0 + y Remove the zero: x = y Simplifying x = y

Solution

x = {-1.625y, y}

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